# 1266. Minimum Time Visiting All Points

On a plane there are `n`

points with integer coordinates `points[i] = [xi, yi]`

. Your task is to find the minimum time in seconds to visit all points.

You can move according to the next rules:

- In one second always you can either move vertically, horizontally by one unit or diagonally (it means to move one unit vertically and one unit horizontally in one second).
- You have to visit the points in the same order as they appear in the array.

**Example 1:**

**Input:**

points = [[1,1],[3,4],[-1,0]]

**Output:**

7

**Explanation: **

One optimal path is

**[1,1]**

-> [2,2] -> [3,3] ->

**[3,4] **

-> [2,3] -> [1,2] -> [0,1] ->

**[-1,0]**

Time from [1,1] to [3,4] = 3 seconds Time from [3,4] to [-1,0] = 4 seconds Total time = 7 seconds

**Example 2:**

**Input:**

points = [[3,2],[-2,2]]

**Output:**

5

**Constraints:**

`points.length == n`

`1 <= n <= 100`

`points[i].length == 2`

`-1000 <= points[i][0], points[i][1] <= 1000`

class Solution { public int minTimeToVisitAllPoints(int[][] points) { int result = 0; int prev_x = points[0][0]; int prev_y = points[0][1]; for (int i = 1; i < points.length; i ++){ int x = points[i][0]; int y = points[i][1]; int diff_x = Math.abs(x - prev_x); int diff_y = Math.abs(y - prev_y); result += Math.min(diff_x,diff_y)+Math.abs(diff_x-diff_y); prev_x = x; prev_y = y; } return result; } }

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