# 1276. Number of Burgers with No Waste of Ingredients

Given two integers `tomatoSlices`

and `cheeseSlices`

. The ingredients of different burgers are as follows:

**Jumbo Burger:**4 tomato slices and 1 cheese slice.**Small Burger:**2 Tomato slices and 1 cheese slice.

Return `[total_jumbo, total_small]`

so that the number of remaining `tomatoSlices`

equal to 0 and the number of remaining `cheeseSlices`

equal to 0. If it is not possible to make the remaining `tomatoSlices`

and `cheeseSlices`

equal to 0 return `[]`

.

**Example 1:**

**Input:**

tomatoSlices = 16, cheeseSlices = 7

**Output:**

[1,6]

**Explantion:**

To make one jumbo burger and 6 small burgers we need 4*1 + 2*6 = 16 tomato and 1 + 6 = 7 cheese. There will be no remaining ingredients.

**Example 2:**

**Input:**

tomatoSlices = 17, cheeseSlices = 4

**Output:**

[]

**Explantion:**

There will be no way to use all ingredients to make small and jumbo burgers.

**Example 3:**

**Input:**

tomatoSlices = 4, cheeseSlices = 17

**Output:**

[]

**Explantion:**

Making 1 jumbo burger there will be 16 cheese remaining and making 2 small burgers there will be 15 cheese remaining.

**Example 4:**

**Input:**

tomatoSlices = 0, cheeseSlices = 0

**Output:**

[0,0]

**Example 5:**

**Input:**

tomatoSlices = 2, cheeseSlices = 1

**Output:**

[0,1]

**Constraints:**

`0 <= tomatoSlices <= 10^7`

`0 <= cheeseSlices <= 10^7`

Should be an easy question..

class Solution { public List<Integer> numOfBurgers(int tomatoSlices, int cheeseSlices) { List<Integer> result = new ArrayList<>(); if (tomatoSlices % 2 ==1 || cheeseSlices * 4 < tomatoSlices || cheeseSlices * 2 > tomatoSlices){ return result; } int x = (tomatoSlices - cheeseSlices*2)/2; result.add(x); result.add(cheeseSlices-x); return result; } }

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